Question

Find the wavelength of a wave traveling at 3.26 e6 m/s with a period of 0.0125 s.

Answer 1

m=40.8km.

Step-by-step explanation:

• The frequency of a wave is the reciprocal of its period, so for the wave in this problem, its frequency is
• f= \frac{1}{T}= \frac{1}{0.0125 s} =80 Hzf=

T

1

=

• 0.0125s

1

=80Hz

The basic relationship bet

where

\lambdaλ is the wavelength of the wave

v is its speed

f is its frequency

If we plug the numbers given by the problem into this equation, we can find the wavelength of this wave:

\lambda= \frac{v}{f}= \frac{3.26 \cdot 10^6 m/s}{80 Hz}=4.08 \cdot 10^4 m=40.8 kmλ=

f v

=

80Hz

3.26⋅10

6

m/s

=4.08⋅10

4

m=40.8km

Answer 2

The frequency of a wave is the reciprocal of its period, so for the wave in this problem, its frequency is

`f= (1)/(T)= (1)/(0.0125 s) =80 Hz`

The basic relationship between wavelength, frequency and speed of a wave is given by:

`\lambda= (v)/(f)`
where

`\lambda` is the wavelength of the wave
v is its speed
f is its frequency

If we plug the numbers given by the problem into this equation, we can find the wavelength of this wave:

`\lambda= (v)/(f)= (3.26 \cdot 10^6 m/s)/(80 Hz)=4.08 \cdot 10^4 m=40.8 km`