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GIVING AWAY 50 POINTS TO WHOEVER SHOWS LEGIT WORK! The lengths of the sides of three squares are s, s + 1, and s + 2. If their total area is 365 cm squared (^2), find their total perimeter.
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Aug 27, 2019
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GIVING AWAY 50 POINTS TO WHOEVER SHOWS LEGIT WORK!
The lengths of the sides of three squares are s, s + 1, and s + 2. If their total area is 365 cm squared (^2), find their total perimeter.
Mathematics
high-school
Jacek Kotowski
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Jacek Kotowski
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S= one length of square 1
S+1 = one length square 2
S+2= one length square 3
Our equation would be
S^2+(S+1)^2+(S+2)^2=365
Idk if it would be called distribute but.. distribute
S^2+S^2+2S+1+S^2+4S+4=365
Add like terms
3S^2+6S-360=0
Divide everything. By 3
S^2+2S-120=0
Factor
(S-10)(S+12)=0
The two solutions are:
S-10=0
S=10
S+12=0
S=-12
Since a length can’t be a negative the only possible solution would be 10
Since a perimeter is all lengths added together we can multiply the length by four to get the perimeter
Square 1
10*4=40
Perimeter is 40cm
Square 2
S+1 =11
11*4=44
Perimeter is 44cm
Square 3
S+2=12
12*4=48
Perimeter is 48cm
Add all the perimeters together to get the total perimeter:
Total perimeter:
40+44+48=132
The total perimeter is 132cm
I hope this helps. Sorry if I messed up anything on here it was kinda hard to keep track of everything. Feel free to ask if you need anything cleared up :)
Wouter Overmeire
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Aug 31, 2019
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Wouter Overmeire
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