2Al + 3H2SO4 -> 3H2 + Al2(SO4)3
First, find your limiting reactant - do this with your moles.
Have:
Al - 5.559mol
H2SO4 - 1.030mol
Need:
Al - 0.6867mol
H2SO4 - 8.339mol
Your limiting reactant is sulfuric acid, so we will use that.
Use your mole bridge and the calculated HAVE of sulfuric acid to do this.
1.030mol * (3/3) = 1.030mol of H2
If you want it in liters, multiply that by 22.4dm^3. If you want it in grams, multiply it by 2.016. Hope this helps!