Question

Kamila has two number cubes each labeled 1 to 6. She is going to conduct an experiment by tossing both cubes a total of 150 times. She will find the sum of the two numbers in each role

a. Possible outcomes? __________
b. Probability of tossing a sum of six? _________
c. How many times should Kamila toss a sum of 7? _________
d. How many times should Kamila toss a sum of 10 or greater? _______

Answer 1

a) There are 36 possible outcomes.
b) The probability of a sum of 6 is 5/36.
c) She should roll a sum of 7 45 times.
d) She should roll a sum of 10 45 times.

Explanation
a) There are 6 outcomes for the first die and 6 outcomes for the second one. By the fundamental counting principle, there are 6*6 = 36 outcomes for both dice together.

b) The ways to get a sum of 6 are:
1&5; 2&4; 3&3; 4&2; 5&1. There are 5 possibilities out of a total of 36, or 5/36.

c) The ways to get a sum of 7 are:
1&6; 2&5; 3&4; 4&3; 5&2; 6&1. There are 6 out of 36, or 6/36=1/6. Since she is rolling the dice 150 times, she should get a sum of 6
1/6(150) = 150/6 = 45 times.

d) The ways to get a sum of 10 or more are:
4&6; 5&5; 6&4; 5&6; 6&5; 6&6

There are 6 ways out of 36, or 6/36 = 1/6. Since she is rolling the dice 150 times, she should get a sum of 10 or more
1/6(150) = 150/6 = 45 times.

Answer 2

Explanation:

a) When two number cubes are thrown possible outcomes are

`6x6  =36`

b) Probability of tossing a sum of 6

Favourable outcomes = (1,5)(5,1)(2,4) (4,2) (3,3)

Hence probability =
`(5)/(36)`

c) For getting 7 favourable outcomes are

(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)

i.e one out of 6 chances.

Hence in 150 times Kamala should toss a sum of 7 ---
`(1)/(6) *150 =25`

d) Favourable outcomes for sum of 10 or greater

= (4,6) (6,4) (5,5) (5,6)(6,5)(6,6)

Probability for getting sum of 10 or greater =
`(6)/(36) =(1)/(6)`

No of times Kamila should toss 10 or greater

=
`(150)/(6) =25`