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1 vote
Make up an equation of the form y = kx +b, the graph of which passes through the following points: C (–19, 31) and D (1, –9)

User Priyanka V
by
6.7k points

1 Answer

3 votes
Try this way:
it is possible to make up the system of two equations using the coordinates of points C and D:
31=k*(-19)+b - if to substitute the coordinates of point C;
-9=k*1+b - if to substitute the coordinates of point D.

\left \{ {{-19k+b=31} \atop {k+b=-9}} \right. \ =\ \textgreater \ \ \left \{ {{20k=-40} \atop {k+b=-9}} \right. \ =\ \textgreater \ \ \left \{ {{k=-2} \atop {b=-7}} \right.
y=-2x-7

answer: y=-2x-7
User Charlotte Sirot
by
6.4k points
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