Question

Graph the function in the interval from 0 to 2Π

y = −2 sin(θ − π3) + 2

Answer 1

Answer with explanation:

The given trigonometric function is

`y= -2 \sin (\Theta -(\pi)/(3))+2\\\\y= -[-2 \sin ((\pi)/(3)-\Theta)]+2\\\\ y=2 \sin ((\pi)/(3)-\Theta)+2`

The sine function has maximum and minimum are 1 and -1, which it will achieve at ,

`\Theta =\pm(2k+1)(\pi)/(2)`

So, the given function will attain maximum and minimum at,

`=\pm(2k+1)(\pi)/(2)-(\pi)/(3)`

for different values of k.

Answer 2

Hello,
Please, see the attached file.
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