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Write the vertex form of the equation of the parabola which has a vertex of (0,0) and contains the point (1,2). A. Y=2x^2. B. Y=2(x-1)^2. C. Y=x^2. D. Y=(x+1)^2+1

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General equation of parabola: y-k = a(x-h)^2

Here the vertex is at (0,0), so we have y-0 = a(x-0)^2, or y = ax^2

All we have to do now is to find the value of the coefficient a.

(1,2) is on the curve. Therefore, 2 = a(1)^2, or 2 = a(1), or a = 2.

The equation of this parabola is y = 2x^2.
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