we know that
the x-intercepts of the quadratic function f(x)=x²−3x−10 is when
f(x)=0
x²−3x−10=0
Group terms that contain the same variable, and move the constant to the opposite side of the equation(x²−3x)=10
Complete the square. Remember to balance the equation by adding the same constants to each side.(x²−3x+2.25)=10+2.25
Rewrite as perfect squares(x-1.5)²=12.25----------> (+/-)[x-1.5]=3.5
(+)[x-1.5]=3.5----> x1=5
(-)[x-1.5]=3.5-----> x2=-2
the answer is
the x-intercepts of the quadratic function are
x=5
x=-2