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The graph of which function has a minimum located at (4, –3)? f(x) = x2 + 4x – 11 f(x) = –2x2 + 16x – 35 f(x) = x2 – 4x + 5 f(x) = 2x2 – 16x + 35
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Apr 8, 2019
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The graph of which function has a minimum located at (4, –3)?
f(x) = x2 + 4x – 11
f(x) = –2x2 + 16x – 35
f(x) = x2 – 4x + 5
f(x) = 2x2 – 16x + 35
Mathematics
high-school
Adam Solchenberger
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Answer:
f(x) = 1/2x^2 – 4x + 5 (the third option)
Explanation:
On ed :)
KeyboardInterrupt
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Apr 10, 2019
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KeyboardInterrupt
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The graph of this function has minimum if a > 0.
Minimum is in point (h; k) where:
Answer:
Any graph of this functions hasn't a minimum located at (4; -3).
If the coordinates of minimum are (4; 3),
then your answer is f(x) = 2x² - 16x + 35
Mark Soric
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Apr 14, 2019
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Mark Soric
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