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Find the distance between the two points. (2, 5) and (–1, –5)

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\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 2 &,& 5~) % (c,d) &&(~ -1 &,& -5~) \end{array} \\\\\\ d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ d=√((-1-2)^2+(-5-5)^2) \\\\\\ d=√((-3)^2+(-10)^2)\implies d=√(109)
User JadziaMD
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√109≈10.44030650 <--- Answer

Distance=(x2x1)2+(y2y1)2

((−1)(2))2+((−5)(5))2

That check sign is the square root, since they wouldnt let me put it in...
User Thomas Schneiter
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