Question

The vertex of a quadratic function is (6, 2), and the y-intercept of the function is (0, −70). The equation of the function in vertex form, f(x)=a(x−h)2+k, is shown.−70=a(0−6) squared+2

Answer 1

THE ANSEWR IS BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB

Explanation:

b the seconed option

Answer 2

The equation of the function in vertex form is represented by
`y = -2\cdot (x-6)^(2)+2`.

Explanation:

Let
`(h,k) = (6,2)` and
`(x,y) = (0, - 70)`, now we substitute on the equation of the quadratic function and solve for
`a`:

`y = a\cdot (x-h)^(2)+k`

`-70 = a\cdot (0-6)^(2)+2`

`-70 = 36\cdot a + 2`

`36\cdot a = -72`

`a = -2`

Therefore, the equation of the function in vertex form is represented by
`y = -2\cdot (x-6)^(2)+2`.