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Faisal Khan · Answer 1 · 2019-11-14T03:30:29+0000

The easiest thing to do to solve all of these is to use the quadratic equation.

$\frac{-b +/- \sqrt{b^(2) -4ac} }{2a}$

The first number (the one attached to x^2) is equal to a. The second number (the one attached to x) is b. The final number (the one with nothing attached) is c.

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