Answer:
The best approximation of AB is 2 meters.
Explanation:
Notice that this situation models a right triangle, when the height, which is a leg of the triangle, is 6 meters.
Also, we know the angle between the ladder and the ground, which is 72°.
To find the distance from A to B, which from the bottom of the ladder to the bottom of the wall, we just need to use trigonometric reasons.
![tan(72\°)=(opposite \ leg)/(adjacent \ leg)](https://img.qammunity.org/2019/formulas/mathematics/high-school/6v3efklkocwm0c51jsaiv0r65y2fvi8nb0.png)
Why we use tangent? Because it relates both legs where we just need to find the adjacent one.
![tan(72\°)=(6)/(AB)\\AB=(6)/(tan(72\°)) \\AB \approx (6)/(3) \\AB \approx 2 \ m](https://img.qammunity.org/2019/formulas/mathematics/high-school/y1n7l5urf7v88j9fdtk74jndh14kc4k7qr.png)
Therefore, the best approximation of AB is 2 meters.