Question

Solve 0= 2t^3-21t^2+ 40t

Answer 1

`0=2t^3-21^2+40t`
switch sides

`2t^3-21t^2+40t=0`
solve factoring

`t(t-8)(2t-5)=0`
using the zero factor principle

`t=0`
solve

`t-8=0:t=8`
solve

`2t-5=0:t= (5)/(2)`

`t=0,t=8,t= (5)/(2)`
Hope this helps