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Solve 0= 2t^3-21t^2+ 40t

User Fabb
by
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1 Answer

3 votes

0=2t^3-21^2+40t
switch sides

2t^3-21t^2+40t=0
solve factoring

t(t-8)(2t-5)=0
using the zero factor principle

t=0
solve

t-8=0:t=8
solve

2t-5=0:t= (5)/(2)

t=0,t=8,t= (5)/(2)
Hope this helps

User Igorti
by
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