Answer:
−8.59 m/s.
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = −4.0 m/s
Acceleration (a) = −0.27 m/s²
Time (t) = 17 s
Final velocity (v) =?
Acceleration is defined as the change of velocity with time. Mathematically, it is expressed as:
Acceleration = change of velocity / time
Acceleration = (final velocity – Initial velocity) / time
a = (v – u) / t
With the above formula, we can determine the velocity of the train after 17 s. This can be obtained as follow:
Initial velocity (u) = −4.0 m/s
Acceleration (a) = −0.27 m/s²
Time (t) = 17 s
Final velocity (v) =?
a = (v – u) / t
−0.27 = (v – –4 ) / 17
−0.27 = (v + 4 ) / 17
Cross multiply
−0.27 × 17 = v + 4
−4.59 = v + 4
Collect like terms
−4.59 – 4 = v
−8.59 = v
v = −8.59 m/s
Thus, the velocity of the train after 17 s is −8.59 m/s.