Question

Ln(2m 8th power) exapnad in logarithmic expression

Answer 1

The rules are ...

`\Longrightarrow \,\, \ln(a\,b)=\ln(a)+\ln(b)`

`\Longrightarrow \,\, \ln(a^(b))=b\ln(a)`

Your expression makes use of both of these rules.

`\ln(2m^(8))=\ln(2)+\ln(m^(8))=\ln(2)+8\ln(m)`

The expanded form is

`\ln(2)+8\ln(m)`