1 Answer

Koji · Answer 1 · 2019-12-27T06:43:05+0000

F(x) = 3x^2 + 9x + 12,
The zeroes of the function are the value of x when F(x)=0.

3x²+ 9x + 12 = 0 (divide all equation by 3)
x²+3x+4 =0

a=1, b=3, c=4

$D= b^(2)-4ac=3^(2) -4*1*4=9-16= -4 \ \textless \ 0, so no real solutions.$

There are no real zeros for this function.

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