Question

mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet. What is the minimum speed she could have been going?

Answer 1

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula:
`r= (c^2)/(8m) + (m)/(2)`
where

`c` is the length of the chord

`m` is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so
`c=52` and
`m=6`. Lets replace those values in our formula:

`r= (52^2)/(8(6)) + (6)/(2)`

`r= (2704)/(48) +3`

`r= (169)/(3) +3`

`r= (178)/(3)`

Next, to find the minimum speed, we are going to use the formula:
`s= √(15fr)`
where

`f` is drag factor

`r` is the radius
We know form our problem that the drag factor is 0.2, so
`f=0.2`. We also know from our previous calculation that the radius is
`(178)/(3)`, so
`r= (178)/(3)`. Lets replace those values in our formula:

`s= \sqrt{(15)(0.2)( (178)/(3)) }`

`s= √(178)`

`s=13.34` mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.