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To solve e4 – 3x = (4/3)x + 9 by graphing, which equations should be graphed?

y = 0
 y = (4/3)x + 9
 y = e4 – 3x – (4/3) + 9
 y = (4/3)x + 9 + e4 – 3x
 y = e4 – 3x

User Eosterberg
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6.6k points

2 Answers

2 votes
y = 4/3x + 9

y = e4 – 3x

There you go love




User PaulP
by
6.4k points
2 votes

Answer:

We have to plot the system of equation as:


  • y=e^4 – 3 x

and y= (4/3)x + 9

step-by-step solution:

We are asked to solve a equation as:

e^4-3 x = (4/3)x + 9.

i.e. it could be represented as:

y=e^4-3 x

and y=(4/3)x + 9.

it could also be written as:

e^4-3 x-(4/3)x - 9=0

To graph the following system we have to graph the equation as:

  • y=e^4 – 3 x

and y= (4/3)x + 9


To solve e4 – 3x = (4/3)x + 9 by graphing, which equations should be graphed? y = 0 y-example-1
User Jason John
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6.1k points