Question

What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall redox equation: 5 Ag (aq) +Mn2 (aq) +4H20()5Ag(s)+ MnO4 (aq) +8H' (aq)

a. 1
b. 2
c. 3
d. 5 (
e.?

Answer 1

Answer:
5 moles of electrons

Step-by-step explanation:

The balance equation is as follow,

5 Ag⁺ + Mn⁺² + 4 H₂O → 5 Ag + MnO₄⁻ + 8 H⁺

Reduction of Ag:

Ag⁺ + 1 e⁻ → Ag
Or,
5 Ag⁺ + 5 e⁻ → 5 Ag

Oxidation of Mn:

Mn⁺² → MnO₄⁻ + 5 e⁻

Result:
Hence 5 moles of Ag⁺ accepts 5 electrons from 1 mole of Mn⁺².