Question

The number of assists per match for the setter on your school's volleyball team has a mean of 58 and a standard deviation of 7. if in the last game he made 77 assists, how many standard deviations is that from the mean? 1.36 standard deviations below the mean 2.71 standard deviations above the mean 1.36 standard deviations above the mean 2.71 standard deviations below the mean

Answer 1

Given that mean=58
standard deviation=7
thus
77 is (77-58)=18 away from 58
This will be:
19/7=2.71

standard deviations from the mean.

Answer: 2.71 standard deviations above the mean

Answer 2

(B)

Explanation:

It is given that The number of assists per match for the setter on your school's volleyball team has a mean of 58 and a standard deviation of 7.

Also, in the last game he made 77 assists, therefore

`77-58=19` assists away from the mean.

Thus, To get the number of standard deviation that 77 is from the mean, we get the z-score which is given as:

`z=(x-\mu)/(\sigma)`

Substituting the given values, we get

`z=(77-58)/(7)`

`z=(19)/(7)`

`z=2.71`

Thus, there are 2.71 standard deviations above the mean.

Hence, option B is correct.