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Suppose you want to build a rectangular sandbox where the width is 5 feet less than the length and the diagonal is 5 feet longer than the length. what are the dimensions of the sandbox?

User Catasaurus
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1 Answer

2 votes
Let L = length
W = L - 5 ←5 feet less than (reverse order - ) the length (L)
D = L + 5
These 3 lengths form a right triangle with D being the hypotenuse, c.
Using the Pythagorean Theorem, a² + b² = c²
L² + (L - 5)² = (L + 5)²
L² + L² - 10L + 25 = L² + 10L + 25
L² - 20L = 0
L = 0 (can't use this answer) or L = 20 (this is a usable answer)
Dimensions of the sandbox 20 ft by 15 ft
Length = 20 ft
Width = 15 ft
Diagonal = 25 ft
User Mstreffo
by
5.7k points
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