Question

Use the given information to find the indicated probability. a and b are mutually exclusive. p(a) = .8, p(b) = .1. find p((a ∪ b)').

Answer 1

If
`A` and
`B` are mutually exclusive, then


`\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)=0.8+0.1=0.9`

Then
`\mathbb P((A\cup B)')=1-\mathbb P(A\cup B)=0.1`.