Use the given information to find the indicated probability. a and b are mutually exclusive. p(a) = .8, p(b) = .1. find p((a ∪ b)').

asked Jan 12, 2019 159k views

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1 vote

and

are mutually exclusive, then

$\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)=0.8+0.1=0.9$

Then
$\mathbb P((A\cup B)')=1-\mathbb P(A\cup B)=0.1$ .

Lukewar answered Jan 16, 2019

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