Question

`(10.5)/(1.79)`


`(16)/(2.19)`
How would I find out the unit rate for these two equations?

Answer 1

well, we can see this case like this, say let's find out how much is it for just 1oz in each case.


`\bf \begin{array}{ccll} oz&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 10.5&1.79\\ 1&x \end{array}\implies \cfrac{10.5}{1}=\cfrac{1.79}{x}\implies x=\cfrac{1\cdot 1.79}{10.5}\implies x\approx 0.17048 \\\\\\ \begin{array}{ccll} oz&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 16&2.19\\ 1&y \end{array}\implies \cfrac{16}{1}=\cfrac{2.19}{y}\implies y=\cfrac{1\cdot 2.19}{16}\implies \boxed{y = 0.136875}`

so, the one with less $/oz is the better deal, because is less bucks per ounce.