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The hyperbola with center at (4, 5), with vertices at (0, 5) and (8, 5), with b = 2.
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The hyperbola with center at (4, 5), with vertices at (0, 5) and (8, 5), with b = 2.

User Leslie Davies
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2 Answers

5 votes

Answer:

Explanation:

The correct answer is (x-4)^2/16 - (y-5)^2/4 = 1

User Willanderson
by
6.0k points
4 votes
The standard form of hyperbola is:
(x-h)²/a²-(y-k)²/b²=1
center:(4,5)
Length of the horizontal transverse axis: 8-5=3=2a
thus
a=3/2
a²=9/4
b=2
b²=4

Hence the equation will be:
(x-4)²/(9/4)-(y-5)²/4=1
simplifying this we get:
[4(x-4)²]/9-(y-5)²/4=1
User Zomb
by
6.2k points
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