Question

When the pressure that a gas exerts on a sealed container changes from 22.5 psi to psi the temperature changes from 110 c to 65.0 c

Answer 1

19.9 psi

Step-by-step explanation:

Answer 2

Gay- Lussacs law states that the pressure of a gas is directly proportional to temperature for a fixed amount of gas at constant volume.
therefore P/T = k
where P - pressure , T - temperature and k - constant

`(P1)/(T1) = (P2)/(T2)`
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - temperature in kelvin - 110 °C + 273 = 383 K
T2 - 65.0 °C + 273 = 338 K
substituting these values in the equation


`(22.5 psi)/(383 K) = (P)/(338K)`
P = 19.9 psi
new pressure is 19.9 psi