Question

Using Hooke's law, F subscript s p r i n g end subscript equals k increment x, find the elastic constant of a spring that stretches 2 cm when a 4 newton force is applied to it.

A. 1/2 N/cm

B. 2 N/cm

C. 4 N/cm

D. 8 N/cm

Answer 1

b. 2N/cm

Step-by-step explanation:

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Answer 2

Let's rewrite Hook's law:

`F=-kx`
where
F is the force
k is the spring's constant
x is the compression/elongation of the spring

Neglecting the sign (since we are not interested in the direction of the force), we can re-arrange the formula and use the data of the problem to find the spring constant:

`k= (F)/(x)= (4 N)/(2 cm)=2 N/cm`

Therefore, the correct answer is B) 2 N/cm.