Question

A cube of iron (Cp = 0.450 J/g•°C) with a mass of 55.8 g is heated from 25.0°C to 49.0°C. How much heat is required for this process?

Answer 1

Q=c(p)*m*Δt
c(p)=0.450 J/g•°C
m= 55.8 g
Δt = t(final)-t(initial)=49.0⁰-25.0⁰ = 24.0⁰C

Q=c(p)*m*Δt = 0.450 J/g•°C * 55.8 g*24.0⁰C ≈ 603 J
Q≈ 603 J