Answer:
Son’s present age, s = 6 years.
Explanation:
Let the son’s present age is s years and father's be f.
We have age of a father is 2 less than 7 times the age of his son.
f = 7s -2
7s - f = 2 -------------------eqn 1
In 3 years, the sum of their ages will be 52.
s + 3 + f + 3 = 52
s + f = 46 -------------------eqn 2
eqn 1 + eqn 2
8s = 48
s = 6
Son’s present age, s = 6 years.