Answer:
1.126 L
Solution:
Let's assume the gas is behaving ideally, then initial and final states of given gas are given as,
P₁ V₁ / T₁ = P₂ V₂ / T₂ ---- (1)
Data Given;
P₁ = 0.572 atm
V₁ = 2.15 L
T₁ = 25 °C + 273 = 298 K
P₁ = 1.00 atm
V₂ = ?
T₂ = 0 °C + 273 = 273 K
Solving equation 1 for V₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting Values,
V₂ = (0.572 atm × 2.15 L × 273 K) ÷ (298 K × 1 atm)
V₂ = 1.126 L