To solve this problem you must apply the proccedure shown below:
1. You have the following equation of a parabola:
1/16(y+3)^2=x+4
2. Rewriting the equation of the parabola, you have:
(y+3)^2=16(x+4)
3. The vertex of the parabola is:
(h,k)=(-4,-3)
3. Now, you must find the coefficient of the unsquared part, as below:
4p=16
p=16/4
p=4
4. As you can see, the y part is squared and p is positive. This means that the parabola that opens to the right.
5. The focus of the parabola has to be 4 units to the right of the vertex. Therefore, the focus is:
(0,-3)
The answer is: (0,-3)