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Given the equation zn(s) + 2 hcl(aq) → zncl2(aq) + h2(g), what mass of hydrogen gas is produced when 2.8 g zn is reacted with excess aqueous hydrocholric acid?
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Given the equation zn(s) + 2 hcl(aq) → zncl2(aq) + h2(g), what mass of hydrogen gas is produced when 2.8 g zn is reacted with excess aqueous hydrocholric acid?

User Lanaru
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1 Answer

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zn+2hcl»zncl2+h2
108+2(1+35.5)»108+71+2
179.2»179+2
108g of zn gives 2g of h when reacted with excess hcl
therefore 2.8g of zn in the same reaction will give 2.8*2/108=0.0518
User Pinedax
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