Question

One object has a charge of +5.0 · 10-6 c, and a second object has a charge of +2.0 · 10-6

c. the objects are 0.5 meters apart. what is the electrostatic force between them?

Answer 1

The electrostatic force between two charged objects is given by

`F=k (q_1 q_2)/(r^2)`
where
k is the Coulomb's constant
q1 is the charge of the first object
q2 is the charge of the second object
r is the separation between the two objects

In our problem:

`q_1=+5.0 \cdot 10^(-6) C`

`q_2 = +2.0 \cdot 10^(-6) C`

`r=0.5 m`
So if we plug these numbers into the equation, we can find the electrostatic force between the two objects:

`F=(8.99 \cdot 10^9 Nm^2C^(-2)) ((5.0 \cdot 10^(-6) C)(2.0 \cdot 10^(-6)C))/((0.5 m)^2)=0.36 N`