Question

PLease help!!!! 3( - 4y - 5) = 8y + 25, Show your work please!!

Answer 1

Now we have to,

→ solve for the required value of y.

Let's solve the problem,

→ 3(-4y - 5) = 8y + 25

→ -12y - 15 = 8y + 25

→ -12y - 8y = 25 + 15

→ -20y = 40

→ y = -40/20

→ [ y = -2 ]

Hence, the value of y is -2.

Answer 2

y = -2

Explanation:

Given equation:

`3(-4y-5)=8y+25`

Distribute:

`\implies 3 \cdot -4y - 3 \cdot 5=8y+25`

`\implies -12y - 15=8y+25`

Add 15 to both sides:

`\implies -12y - 15+15=8y+25+15`

`\implies -12y =8y+40`

Subtract 8y from both sides:

`\implies -12y-8y =8y+40-8y`

`\implies -20y =40`

Divide both sides by -20:

`\implies (-20y)/(-20) =(40)/(-20)`

`\implies y =-2`