Question

Please help condense into a single logarithm:

Answer 1

The first step for solving this expression is to write the number below ㏒ in exponential form.
㏒
`_( 3^(2) )`(x) + 2㏒
`_( 3^(2) )`(y) - ㏒
`_(2)`(z)
Using ㏒
`_(a^(y) )`(b) =
`(1)/(y)` × ㏒
`_(a)`(b),, transform the expressions with ㏒
`_( 3^(2) )`.

`(1)/(2)` × ㏒
`_(3)`(x) +
`(1)/(2)` × ㏒
`_(3)`(y) - ㏒
`_(2)`(z)
Lastly,, reduce the numbers with 2 to find your final answer.

`(1)/(2)` × ㏒
`_(3)`(x) + ㏒
`_(3)`(y) - ㏒
`_(2)`(z)
This means that the correct answer to your question is
`(1)/(2)` × ㏒
`_(3)`(x) + ㏒
`_(3)`(y) - ㏒
`_(2)`(z).
Let me know if you have any further questions.
:)