Question

The path of a rocket ship is given by the parametric equations x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch. Where is the ship after 10 seconds?

A.) (3,4)
B.) (3,5)
C.) (30,401)
D.) (30,501)

Answer 1

x(t)=3t
y(t)=4t^2+1

Time (seconds):

Where is the ship after 10 seconds?
t=10→Position: Point: P=(x(t), y(t))=(x(10), y(10))=?

t=10→x(10)=3(10)→x(10)=30
t=10→y(10)=4(10)^2+1=4(100)+1=400+1→y(10)=401

Position: P=(x(10), y(10))=(30, 401)

Answer: Option C.) (30, 401)