Question

A car came to a stop from a speed of 35 m/s in a time of 8.1 seconds. What was the acceleration of the car?

A. -10.2 m/s
B. -5.11 m/s
C. -4.32 m/s
D. -9.80 m/s

Answer 1

Simply subtract the two velocities and divide by 8.1,


`(0 - 35)/(8.1) = - 4.32`

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Answer 2

The acceleration of the car is -4.32 m/s^2.

(C) is correct.

Step-by-step explanation:

Given that,

Speed of car u= 35 m/s

Time t = 8.1 s

We need to calculate the acceleration

using equation of motion

`v = u+at`

Where, v = final velocity

u = initial velocity

t = time

a = acceleration

`0=35+a*8.1`

`a = -(35)/(8.1)`

`a = -4.32\ m/s^2`

Hence, The acceleration of the car is -4.32 m/s^2.