Question

How many moles of Pb(NO3)2 are required if 8 moles of PbCI2 are produced?

Answer 1

PbCl₂ can be synthesized from Pb(NO₃)₂ using various reagents. I will be using HCl as follow,

Pb(NO₃)₂ + 2 HCl → PbCl₂ + 2 HNO₃

According to equation,

1 mole of PbCl₂ is formed by = 1 mole of Pb(NO₃)₂
So,
8 moles of PbCl₂ will be produced by = X moles of Pb(NO₃)₂

Solving for X,
X = (8 mol × 1 mol) ÷ 1 mol

X = 8 mol of Pb(NO₃)₂
Result:
8 mol of Pb(NO₃)₂ are required to produce 8 moles of PbCl₂.