Answer:
Explanation:
The given expression is
3In x – 2In (x + 1)
We would apply the rule of logarithm which is expressed as
ylog x = logx^y
Therefore,
3In x – 2In (x + 1) = lnx^3 - ln(x + 1)^2
We would apply another rule of logarithm which is expressed as
loga - logb = loga/b
Therefore
lnx^3 - ln(x + 1)^2 = ln x^3 /(x + 1)^2