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Find the reciprocal of (7/5)^-2​

User Andrie
by
9.4k points

2 Answers

10 votes

Explanation:


\rightsquigarrow
\tt{((7)/(5))^(-2) }


\rightsquigarrow
\tt{(1)/(((7)/(5))^2) }

so,


\rightsquigarrow
\tt{(1)/((49)/(35)) }


\rightsquigarrow
\tt{(35)/(49) }

reciprocal:-


\hookrightarrow
\tt{(49)/(35 ) }

User JFFF
by
7.9k points
6 votes

Answer:

(5/7)^(-2)

Explanation:


((7)/(5))^(-2) =(7^(-2))/(5^(-2))

Reciprocal =
(5^(-2))/(7^(-2)) = ((5)/(7))^(-2)

User Paebbels
by
8.0k points

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