Answer:
The compound interest after 2 years of loan is $1,050 .
Explanation:
Given as :
The principal value = p = $5000
The rate of interest = r = 10%
The time period for the loan = t = 2 years
Let the compound interest = C.I
Now, From Compound Interest method
Amount = Principal ×
![(1+(\textrm rate)/(100))^(\textrm time)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8vyvx45u1j0hhdziyk2l5d1e1b8uz8wocs.png)
Or, A = p ×
![(1+(\textrm r)/(100))^(\textrm t)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3ge80ih8t4r8epphg8xfemr3nb1bkzhuex.png)
Or, A = $5000 ×
![(1+(\textrm 10)/(100))^(\textrm 2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t9d33uhpw6631nauoj08wdco2ztemanx9e.png)
Or, A = $5000 × (1.1)²
Or, A = $5000 × 1.21
Or, A = $6,050
So, The Amount after 2 years = A = $6,050
Now, Again
Compound Interest = Amount - Principal
So, C.I = A - p
Or, C.I = $6,050 - $5000
∴ C.I = $1,050
So, The compound interest = C.I = $1,050
Hence,The compound interest after 2 years of loan is $1,050 . Answer