Question

Find all solutions of sin x - square 3-3 sin^2x=0

Answer 1

C)
`60^\circ+n360^\circ,120^\circ+n360^\circ`

Explanation:

`sinx-√(3-3sin^2x)=0`

`sinx=√(3-3sin^2x)`

`sin^2x=3-3sin^2x`

`4sin^2x=3`

`sin^2x=(3)/(4)`

`sinx=\pm\sqrt{(3)/(4) }`

`sinx=\pm(√(3))/(2)`

`x=(\pi)/(3)+2\pi n,(2\pi)/(3)+2\pi n`

`x=60^\circ+n360^\circ,120^\circ+n360^\circ`

Therefore, the correct option is C