Question

An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

A . 4.3
B . 4.8
C . 5.3
D . 5.8
PLSSS HELP !!! GUYSSS

Answer 1

A

Explanation:

I hope this helps.

Answer 2

Option C . 5.3 in

Explanation:

The complete question is

An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

A rectangle is shown divided into 4 smaller rectangles that are related to the size of the edges. The top edge is labeled 10 inches and 2 inches, above the top two rectangles. The top two rectangles are much larger than the bottom two rectangles

Let

x ----> the length of the art project in inches

y ----> the width of the art project in inches

we know that

The area of the rectangular art project is equal to

`A=xy`

we have

`A=63.6\ in^2`

so

`63.6=xy` ----> equation A

`x=10+2=12\ in`

substitute the value of x in the equation A

`63.6=(12)y`

solve for y

`y=63.6/12\\y=5.3\ in`