Question

Write the equation of the line that passes through (-4, 8) and is parallel to the line that passes through (2, 1) and (-2, -1).

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Answer 1

Explanation:

(2,1), (-2,-1)

slope(m) = (-1-1) / (-2 - 2) = -2/-4 = 1/2

parallel lines will have the same slope

y = mx + b

slope(m) = 1/2

(-4,8)...x = -4 and y = 8

now sub and find b, the y int

8 = 1/2(-4) + b

8 = -2 + b

8 + 2 = b

10 = b

so ur equation is : y = 1/2x + 10 <==

Answer 2

`\displaystyle x - 2y = -20\:OR\:y = (1)/(2)x + 10`

Step-by-step explanation:

First, find the rate of change [slope]:

`\displaystyle (-y_1 + y_2)/(-x_1 + x_2) = m \\ \\ (-1 - 1)/(-2 - 2) = (-2)/(-4) = (1)/(2)`

Now plug [−4, 8] into the Slope-Intercept Formula instead of the Point-Slope Formula because you get it done much more swiftly:

8 = ½[−4] + b

−2

`\displaystyle 10 = b \\ \\ y = (1)/(2)x + 10`

If you want it in Standard Form:

y = ½x + 10

- ½x - ½x

__________

−½x + y = 10 [We do not want fractions in our standard equation, so multiply by the denominator to get rid of it.]

−2[−½x + y = 10]

`\displaystyle x - 2y = -20`

I am joyous to assist you anytime.