Question

Which is the equation of an asymptote of the hyperbola whose equation is

(x - 2)²/4 (y - 1)²/36 = 1?

A. y = −3x − 5

B. y = −3x − 7

C. y = 3x − 5

D. y = 3x + 7

Answer 1

Answer:C y=3x-5

Explanation:

just took the review test on edg

Answer 2

C. y = 3x - 5

Explanation:

Given the general equation of a hyperbola:

`((x-h)^(2) )/(a^(2))-((y-k)^(2) )/(b^(2))=1`

The equation for the asymptote line is given by:

`y=k+(b)/(a) (x-h)`

In your problem, we have

`((x-2)^(2) )/(4)-((y-1)^(2) )/(36)=1`

we have:

h=2,

k=1

a²=4 --> a=2, im just taking the squareroot

b²=36 --> b=6

put it into your equation

`y=k+(b)/(a) (x-h)`

`y=1+(6)/(2) (x-2)`

y = 1 + 3(x-2)

y = 1 + 3x - 6

y = 3x - 5