Question

Find the value of x in the rhombus

please help:)

Answer 1

We know, diagonal of a rhombus bisect the angle into halves.

Also, opposite angles in a rhombus are equal to each other.

`2( 4x^2 - 36) = 2( 3x^2 - 5x )\\\\4x^2 - 36 = 3x^2 - 5x\\\\x^2 + 5x - 36 = 0\\\\x^2 + 6x - x - 36 = 0\\\\x( x + 6 ) - ( x + 6 ) = 0\\\\x = 1 \ and \ x = -6`

Therefore, the value of x is 1 and -6.