Question

a 500 kg car is accelerated from rest by a force of 2000 N for a displacement of 400m. what is the speed of the car at the end of 400 M?

Answer 1

57 m/s

Step-by-step explanation:

Use Newton's second law to find the acceleration.

F = ma

2000 N = (500 kg) a

a = 4 m/s²

Given:

Δx = 400 m

v₀ = 0 m/s

a = 4 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (4 m/s²) (400 m)

v ≈ 57 m/s