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4 votes
Write an equation that describes the line
that passes through (2, 2) and (0, -3).

User Yekta
by
8.1k points

1 Answer

3 votes

Answer:

f(x) =
(5)/(2)x

Explanation:

The first thing we need to find is the slope of the line able to pass through the given two points. Right now we have y = mx + b (linear function equation) and we need to find m.

  • Using the slope formula or
    m = \frac{\text{rise}}{\text{run}} = (y_2 - y_1)/(x_2 - x_1) and plugging in the given points' x and y values:


(-3-2)/(0-2) =
(-5)/(-2) =
(5)/(2)

  • The slope of the line is that for every 5 units the line goes upwards, it goes 2 units to the right.

Our equation is now y =
(5)/(2)x + b
. If you were in need of it, b gives the line's y-intercept, the place where it hits the y-axis. In this case you do not need b because the only specified conditions in the problem are the units the line hits.

Our final equation is:

f(x) =
(5)/(2)x

User Raz Harush
by
7.9k points

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