Question

The scheme function (mult2-diff Ist) should take one argument, a list of numbers, and results in multiplying each number in the list by two and then computing the difference of those numbers, e.g.: (mult2-diff'(912)) should evaluate to the difference of 18, 2 and 4: (18-2)-4, or 12. Finish mult2-diff below: (define (mult2-diff lst) (if

Answer 1

The solution code is written in Python.

1. def mult2_diff(lst):
2. num_list = []
4. for x in lst:
5. num_list.append(x * 2)
7. diff = num_list[0]
8. for i in range(1, len(num_list)):
9. diff = diff - num_list[i]
11. print(diff)

Step-by-step explanation:

Firstly, based on the requirement stated in the question, define a function mult2_diff() that takes one argument, lst, which is a list of numbers (Line 1).

This function is expected to multiply each number in the list by two and then followed with computing the difference. To do so, let's try to attempt the first function task, multiplying numbers. Create a new list, num_list, to hold the multiplied numbers (Line 2). Use a for loop to traverse through each number in the input list, lst, and multiply each of them by two and add it to the num_list (Line 4-5).

To attempt the second function task, create another variable, diff, to hold the value of calculated difference between the numbers in the num_list. Initialize diff with the first number in the num_list. Use a another for-loop to traverse through each number in the num_list starting with second index, 1, and calculate the difference between the diff and the current number extracted from the num_list through indexing.

At last print the output of diff (Line 11).