Answer: n = 78
Therefore, Determine the minimum sample size required when you want to be 98% confident that the sample mean is within two units of the population mean is 78
n >/= 78
Explanation:
Given;
Standard deviation r= 7.55
Margin of error E= 2.0
Confidence interval of 98%
Z at 98% = 2.33
Margin of error E = Z(r/√n)
Making n the subject of formula, we have
n = (Z×r/E)^2
n = (2.33 × 7.55/2.0)^2
n = (8.79575)^2
n = 77.3652180625
n >/= 78
Therefore, Determine the minimum sample size required when you want to be 98% confident that the sample mean is within two units of the population mean is 78